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2x=x^2+15
We move all terms to the left:
2x-(x^2+15)=0
We get rid of parentheses
-x^2+2x-15=0
We add all the numbers together, and all the variables
-1x^2+2x-15=0
a = -1; b = 2; c = -15;
Δ = b2-4ac
Δ = 22-4·(-1)·(-15)
Δ = -56
Delta is less than zero, so there is no solution for the equation
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